\( \begin{array}{ll}\text { 1. } & 5 x-8=12 \\ \text { 2. } & 2(y+4)=14 \\ \text { 3. } & 3 a+7-a=9 \\ \text { 4. } b / 4+3=8 \\ \text { 5. } & -3 c+5=-10\end{array} \)

Let's solve these step by step with a touch of fun! For the first equation, \( 5x - 8 = 12 \): Add 8 to both sides and you get \( 5x = 20 \). Now, divide by 5 to find \( x = 4 \). Voila! Now, onto the second equation, \( 2(y + 4) = 14 \): Divide everything by 2 to simplify it down to \( y + 4 = 7 \). Subtract 4 from both sides and there you have \( y = 3 \)! Next, for the third one, \( 3a + 7 - a = 9 \): Combine like terms to get \( 2a + 7 = 9 \). Subtract 7 and you’ll see \( 2a = 2 \), leading to \( a = 1 \). Easy peasy! Now, for equation four, \( \frac{b}{4} + 3 = 8 \): Subtract 3 from both sides, which gives you \( \frac{b}{4} = 5 \). Multiply by 4 to finally see that \( b = 20 \). Lastly, for equation five, \( -3c + 5 = -10 \): Subtract 5 to get \( -3c = -15 \). Dividing by -3, you'll conclude that \( c = 5 \). Final Answers: 1. \( x = 4 \) 2. \( y = 3 \) 3. \( a = 1 \) 4. \( b = 20 \) 5. \( c = 5 \) Now go out and show off those math skills! 🧠✨