$$ \begin{array}{ll} ext { 1. } & 5 x-8=12 \ ext { 2. } & 2(y+4)=14 \ ext { 3. } & 3 a+7-a=9 \ ext { 4. } b / 4+3=8 \ ext { 5. } & -3 c+5=-10\end{array} $$

Question

$$ \begin{array}{ll}	ext { 1. } & 5 x-8=12 \ 	ext { 2. } & 2(y+4)=14 \ 	ext { 3. } & 3 a+7-a=9 \ 	ext { 4. } b / 4+3=8 \ 	ext { 5. } & -3 c+5=-10\end{array} $$

UpStudy AI · Accepted Answer

Let's solve each of the given equations step by step.

---

**1. Solve for $$ x $$ in the equation:**
$$
5x - 8 = 12
$$
**Solution:**
$$
\begin{align*}
5x - 8 &= 12 \
5x &= 12 + 8 \
5x &= 20 \
x &= \frac{20}{5} \
x &= 4
\end{align*}
$$

**Answer:** $$ x = 4 $$

---

**2. Solve for $$ y $$ in the equation:**
$$
2(y + 4) = 14
$$
**Solution:**
$$
\begin{align*}
2(y + 4) &= 14 \
y + 4 &= \frac{14}{2} \
y + 4 &= 7 \
y &= 7 - 4 \
y &= 3
\end{align*}
$$

**Answer:** $$ y = 3 $$

---

**3. Solve for $$ a $$ in the equation:**
$$
3a + 7 - a = 9
$$
**Solution:**
$$
\begin{align*}
3a + 7 - a &= 9 \
2a + 7 &= 9 \
2a &= 9 - 7 \
2a &= 2 \
a &= \frac{2}{2} \
a &= 1
\end{align*}
$$

**Answer:** $$ a = 1 $$

---

**4. Solve for $$ b $$ in the equation:**
$$
\frac{b}{4} + 3 = 8
$$
**Solution:**
$$
\begin{align*}
\frac{b}{4} + 3 &= 8 \
\frac{b}{4} &= 8 - 3 \
\frac{b}{4} &= 5 \
b &= 5 \times 4 \
b &= 20
\end{align*}
$$

**Answer:** $$ b = 20 $$

---

**5. Solve for $$ c $$ in the equation:**
$$
-3c + 5 = -10
$$
**Solution:**
$$
\begin{align*}
-3c + 5 &= -10 \
-3c &= -10 - 5 \
-3c &= -15 \
c &= \frac{-15}{-3} \
c &= 5
\end{align*}
$$

**Answer:** $$ c = 5 $$

---

**Summary of Solutions:**
$$
\begin{cases}
x = 4 \
y = 3 \
a = 1 \
b = 20 \
c = 5
\end{cases}
$$
The solutions are: - $$ x = 4 $$ - $$ y = 3 $$ - $$ a = 1 $$ - $$ b = 20 $$ - $$ c = 5 $$

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