Question
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Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks. A couple of friends decide to race each other. Leon can run 4 yards per second, whereas Michael can run 7 yards per second. Because he is slower, Leon also gets a head start of 39 yards. Shortly after they start running, Michael will catch up to Leon. How far will Michael have to run? How long will that take? Michael will catch up to Leon after running \( \square \) yards in \( \square \) seconds.

Ask by Bradley Howell. in the United States
Jan 12,2025

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Tutor-Verified Answer

Answer

Michael will catch up to Leon after running **91** yards in **13** seconds.

Solution

Certainly! Let's break down the problem step by step by setting up a system of equations, solving it using substitution, and then filling in the blanks with the obtained values. ### **Step 1: Define the Variables** - Let \( t \) be the time in seconds it takes for Michael to catch up to Leon. - Let \( d \) be the distance in yards that Michael runs to catch up. ### **Step 2: Set Up the Equations** 1. **Leon’s Distance:** - Leon runs at a speed of 4 yards per second. - He also has a head start of 39 yards. - Therefore, Leon's total distance can be expressed as: \[ \text{Leon’s Distance} = 4t + 39 \] 2. **Michael’s Distance:** - Michael runs at a speed of 7 yards per second. - Therefore, Michael's distance is: \[ \text{Michael’s Distance} = 7t \] ### **Step 3: Set the Equations Equal** Since Michael catches up to Leon when both have run the same distance: \[ 7t = 4t + 39 \] ### **Step 4: Solve for \( t \)** \[ 7t - 4t = 39 \\ 3t = 39 \\ t = \frac{39}{3} \\ t = 13 \text{ seconds} \] ### **Step 5: Find \( d \) (Michael’s Distance)** \[ d = 7t = 7 \times 13 = 91 \text{ yards} \] ### **Final Answer** Michael will catch up to Leon after running **91** yards in **13** seconds.

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Let \( t \) be the time in seconds that Michael runs, and \( d_L \) and \( d_M \) be the distances Leon and Michael run, respectively. We can express their distances based on their speeds and the head start that Leon has. Since Leon has a head start of 39 yards, the equations are: 1. \( d_L = 4t + 39 \) (distance Leon runs) 2. \( d_M = 7t \) (distance Michael runs) Setting the distances equal to each other when Michael catches up: \[ 4t + 39 = 7t \] Now, solve for \( t \): \[ 39 = 7t - 4t \] \[ 39 = 3t \] \[ t = 13 \text{ seconds} \] Now substitute \( t \) back into the equation for \( d_M \): \[ d_M = 7(13) = 91 \text{ yards} \] So, Michael will catch up to Leon after running \( 91 \) yards in \( 13 \) seconds.

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