Solve $$ x^{3}-2 x^{2}-15 x+36=0 $$ by factorising.

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Solve the equation $$ x^{3}-2x^{2}-15x+36=0 $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$x^{3}-2x^{2}-15x+36=0$$
- step1: Factor the expression:
  $$\left(x-3ight)^{2}\left(x+4ight)=0$$
- step2: Separate into possible cases:
  $$\begin{align}&\left(x-3ight)^{2}=0\&x+4=0\end{align}$$
- step3: Solve the equation:
  $$\begin{align}&x=3\&x=-4\end{align}$$
- step4: Rewrite:
  $$x_{1}=-4,x_{2}=3$$
The solutions to the equation $$x^{3}-2x^{2}-15x+36=0$$ by factorizing are $$x=-4$$ and $$x=3$$.
The solutions are $$x=-4$$ and $$x=3$$.

Solve by factorising.

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