3. \( 5 \frac{3}{8}+\left(6 \frac{3}{4}-4 \frac{1}{8}\right) \)

To solve the expression \( 5 \frac{3}{8}+\left(6 \frac{3}{4}-4 \frac{1}{8}\right) \), we first deal with the parentheses. Convert the mixed numbers into improper fractions: - \( 6 \frac{3}{4} = \frac{27}{4} \) - \( 4 \frac{1}{8} = \frac{33}{8} \) Now, let's convert \( \frac{27}{4} \) to have a common denominator with \( \frac{33}{8} \): - \( \frac{27}{4} = \frac{54}{8} \) Now perform the subtraction: \[ \frac{54}{8} - \frac{33}{8} = \frac{21}{8} \] Now, add \( 5 \frac{3}{8} \): - Convert \( 5 \frac{3}{8} \) to improper fraction: \( 5 \frac{3}{8} = \frac{43}{8} \) Now perform the addition: \[ \frac{43}{8} + \frac{21}{8} = \frac{64}{8} = 8 \] So, the result is \( 8 \).