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This question has two parts. First, answer Part A. Then, answer Part B. Part A A triangle has sides with lengths 8,15 , and 17 . Which of the following verifies this is a Pythagorean triple? O A) \( 8^{2}+15^{2}=17^{2} \) B) \( 8^{2}+17^{2}=15^{2} \) C) \( 15^{2}+17^{2}=8^{2} \) Part B Approximate these side lengths do not form a Pythagorean triple. ascending order. D angles in this triangle to the nearest degree and list in Degrees and

Ask by Bowen Griffiths. in the United States
Jan 23,2025

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Answer

**Part A:** Option A) \(8^{2} + 15^{2} = 17^{2}\) verifies the Pythagorean triple. **Part B:** The triangle's angles, in ascending order, are 28°, 62°, and 90°.

Solution

**Part A** To verify whether the side lengths \(8\), \(15\), and \(17\) form a Pythagorean triple, we check if the Pythagorean theorem holds true. The theorem states that in a right-angled triangle: \[ \text{(Leg 1)}^{2} + \text{(Leg 2)}^{2} = \text{(Hypotenuse)}^{2} \] Let's evaluate each option: - **Option A:** \(8^{2} + 15^{2} = 17^{2}\) \[ 64 + 225 = 289 \quad \Rightarrow \quad 289 = 289 \quad \text{(True)} \] - **Option B:** \(8^{2} + 17^{2} = 15^{2}\) \[ 64 + 289 = 225 \quad \Rightarrow \quad 353 \neq 225 \quad \text{(False)} \] - **Option C:** \(15^{2} + 17^{2} = 8^{2}\) \[ 225 + 289 = 64 \quad \Rightarrow \quad 514 \neq 64 \quad \text{(False)} \] **Answer:** **Option A) \(8^{2} + 15^{2} = 17^{2}\)** verifies that the side lengths form a Pythagorean triple. --- **Part B** Given that the triangle with sides \(8\), \(15\), and \(17\) is a right-angled triangle (as verified in Part A), we can find the measures of the three angles. 1. **Identify the Right Angle:** - The longest side, \(17\), is the hypotenuse. - Therefore, the angle opposite to the hypotenuse is \(90^\circ\). 2. **Calculate the Other Two Angles:** - **Angle opposite the side of length \(8\):** \[ \sin(\theta) = \frac{8}{17} \quad \Rightarrow \quad \theta = \sin^{-1}\left(\frac{8}{17}\right) \approx 28^\circ \] - **Angle opposite the side of length \(15\):** \[ \sin(\phi) = \frac{15}{17} \quad \Rightarrow \quad \phi = \sin^{-1}\left(\frac{15}{17}\right) \approx 62^\circ \] 3. **Arrange the Angles in Ascending Order:** \[ 28^\circ, \quad 62^\circ, \quad 90^\circ \] **Answer:** The triangle's angles, in ascending order and rounded to the nearest degree, are **28°, 62°, and 90°**.

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To verify if the sides 8, 15, and 17 form a Pythagorean triple, we check option A: \( 8^{2}+15^{2}=17^{2} \). When we calculate this, \( 64 + 225 = 289 \), which equals \( 17^{2} \). Therefore, this confirms that 8, 15, and 17 do indeed form a Pythagorean triple! Now, for the angles of our triangle, we can use the cosine rule. To find angle A opposite side 8, we apply: \[ A = \cos^{-1} \left( \frac{b^2 + c^2 - a^2}{2bc} \right) \] By calculating, we find that the angles approximate to about 28°, 62°, and 90°, as the side opposite the longest length (17) will be the right angle. So, in ascending order, the angles are approximately 28°, 62°, and 90°.

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