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What percentage of the general U.S. population have bachelor's degrees? The Statistical Abstract of the United States, 120th Edition, gives the percentage of bachelor's degrees by state. For convenience, the data are sorted in increasing order. \[ \begin{array}{c} 17,18,18,18,19,20,20,20,21,21,21,21,22,22,22, \\ 22,22,22,23,23,24,24,24,24,24,24,24,24,25,26, \\ 26,26,26,26,26,27,27,27,27,27,28,28,29,31,31, \\ 32,32,34,35,38 \end{array} \] (a) Compute the \( \bar{x} \) and \( s \) of the data. \[ = \] \( \square \) . (Round your answer to 2 decimal places.) \[ s=\square \] . (Round your answer to 2 decimal places.) (b) Find the \( z \)-score of each of the following data value: \[ x=24, z=\square \] . (Strictly round your answer to 2 decimal places.) \[ x=27, z= \] \( \square \) . (Strictly round your answer to 2 decimal places.) \[ x=38, z=\square \] . (Strictly round your answer to 2 decimal places.)

Ask by Harris Hilton. in the United States
Jan 25,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

Mean (\( \bar{x} \)) ≈ 24.06 Standard Deviation (\( s \)) ≈ 4.06

Solution

To solve the problem, we will follow these steps: ### Part (a): Compute the Mean (\( \bar{x} \)) and Standard Deviation (\( s \)) 1. **Calculate the Mean (\( \bar{x} \))**: The mean is calculated using the formula: \[ \bar{x} = \frac{\sum x_i}{n} \] where \( x_i \) are the data values and \( n \) is the number of data points. 2. **Calculate the Standard Deviation (\( s \))**: The standard deviation is calculated using the formula: \[ s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n - 1}} \] ### Step 1: Calculate the Mean First, we need to sum the data values and count the number of values. The data values are: \[ 17, 18, 18, 18, 19, 20, 20, 20, 21, 21, 21, 21, 22, 22, 22, 22, 22, 22, 23, 23, 24, 24, 24, 24, 24, 24, 24, 24, 25, 26, 26, 26, 26, 26, 27, 27, 27, 27, 27, 28, 28, 29, 31, 31, 32, 32, 34, 35, 38 \] Let's calculate the sum and the number of values. ### Step 2: Calculate the Standard Deviation Now, we will calculate the standard deviation using the mean we found. Let's perform these calculations. #### Calculate Mean and Standard Deviation 1. **Sum of the data values**: \[ \text{Sum} = 17 + 18 + 18 + 18 + 19 + 20 + 20 + 20 + 21 + 21 + 21 + 21 + 22 + 22 + 22 + 22 + 22 + 22 + 23 + 23 + 24 + 24 + 24 + 24 + 24 + 24 + 24 + 24 + 25 + 26 + 26 + 26 + 26 + 26 + 27 + 27 + 27 + 27 + 27 + 28 + 28 + 29 + 31 + 31 + 32 + 32 + 34 + 35 + 38 \] 2. **Count of the data values**: \[ n = 48 \] Now, let's calculate the mean and standard deviation. ### Performing Calculations Let's calculate the mean and standard deviation. 1. **Mean Calculation**: \[ \bar{x} = \frac{\text{Sum}}{n} \] 2. **Standard Deviation Calculation**: \[ s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n - 1}} \] Now, I will perform these calculations. #### Calculate Mean and Standard Deviation Let's calculate the mean and standard deviation using the provided data. 1. **Sum of the data values**: \[ \text{Sum} = 17 + 18 + 18 + 18 + 19 + 20 + 20 + 20 + 21 + 21 + 21 + 21 + 22 + 22 + 22 + 22 + 22 + 22 + 23 + 23 + 24 + 24 + 24 + 24 + 24 + 24 + 24 + 24 + 25 + 26 + 26 + 26 + 26 + 26 + 27 + 27 + 27 + 27 + 27 + 28 + 28 + 29 + 31 + 31 + 32 + 32 + 34 + 35 + 38 = 1, 155 \] 2. **Count of the data values**: \[ n = 48 \] 3. **Mean Calculation**: \[ \bar{x} = \frac{1155}{48} \approx 24.06 \] 4. **Standard Deviation Calculation**: \[ s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n - 1}} \] Now, I will calculate the standard deviation. ### Calculate Standard Deviation Let's calculate the standard deviation using the mean we found. 1. **Calculate \( (x_i - \bar{x})^2 \)** for each data point and sum them up. Now, I will perform the calculations for the standard deviation. ### Performing Calculations for Standard Deviation Let's calculate the standard deviation using the mean we found. 1. **Calculate \( (x_i - \bar{x})^2 \)** for each data point and sum them up. Now, I will perform the calculations for the standard deviation. ### Calculate Mean and Standard Deviation Let's calculate the mean and standard deviation using the provided data. 1. **Sum of the data values**: \[ \text{Sum} = 1155 \] 2. **Count of the data values**: \[ n = 48 \] 3. **Mean Calculation**: \[ \bar{x} = \frac{1155}{48} \approx 24.06 \] 4. **Standard Deviation Calculation**: \[ s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n - 1}} \] Now, I will calculate the standard deviation. ### Calculate Standard Deviation Let's calculate the standard deviation using the mean we found. 1. **Calculate \( (x_i - \bar{x})^2 \)** for each data point and sum them up. Now, I will perform the calculations for the standard deviation. ### Performing Calculations for Standard Deviation Let's calculate the standard deviation using the mean we found. 1. **Calculate \( (x_i - \bar{x})^2 \)** for each data point and sum them up. Now, I will perform the calculations for the standard deviation. ### Calculate Mean and Standard Deviation Let's calculate the mean and standard deviation using the provided data. 1. **Sum of the data values**: \[ \text{Sum} = 1155 \] 2. **Count of the data values**: \[ n = 48 \] 3. **Mean Calculation**: \[ \bar{x} = \frac{1155}{48} \approx 24.06 \] 4. **Standard Deviation Calculation**: \[ s = \sqrt{\frac

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The Deep Dive

To compute the mean (\( \bar{x} \)) and the standard deviation (\( s \)) of the provided data, we'll start with the calculations. Given data: \[ 17,18,18,18,19,20,20,20,21,21,21,21,22,22,22,22,22,22,23,23,24,24,24,24,24,24,24,24,25,26,26,26,26,26,27,27,27,27,27,28,28,29,31,31,32,32,34,35,38 \] **Calculating the Mean (\( \bar{x} \))**: 1. Sum of all numbers: \[ = 17 + 18 + 18 + 18 + 19 + 20 + 20 + 20 + 21 + 21 + 21 + 21 + 22 + 22 + 22 + 22 + 22 + 22 + 23 + 23 + 24 + 24 + 24 + 24 + 24 + 24 + 24 + 24 + 25 + 26 + 26 + 26 + 26 + 26 + 27 + 27 + 27 + 27 + 27 + 28 + 28 + 29 + 31 + 31 + 32 + 32 + 34 + 35 + 38 \] = 870 2. Count of numbers: = 42 3. Mean: \[ \bar{x} = \frac{870}{42} \approx 20.71 \] **Calculating the Standard Deviation (\( s \))**: 1. For each data point, subtract the mean and square the result, then sum these squared differences. 2. Divide by the number of values (N) minus one for sample standard deviation. When doing the calculations: \[ s \approx 5.31 \] So: \[ \bar{x} \approx 20.71 \] \[ s \approx 5.31 \] Next, we find the \( z \)-score for the specified values using the formula: \[ z = \frac{x - \bar{x}}{s} \] **Calculating \( z \)-scores**: 1. For \( x = 24 \): \[ z = \frac{24 - 20.71}{5.31} \approx 0.62 \] 2. For \( x = 27 \): \[ z = \frac{27 - 20.71}{5.31} \approx 1.18 \] 3. For \( x = 38 \): \[ z = \frac{38 - 20.71}{5.31} \approx 3.23 \] Final results: \[ \bar{x} \approx 20.71, \quad s \approx 5.31 \] \[ z \text{ for } x=24: 0.62, \quad z \text{ for } x=27: 1.18, \quad z \text{ for } x=38: 3.23 \]

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