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Find the zero(s) of \( f(x)=8.53 x^{2}-9.81 x-5.69 \) to three decimal places. If there is more than one zero, write all them on the same line, separated by commas.

Ask by Zimmerman Cox. in the United States
Jan 21,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The zeros of the function are approximately -0.424 and 1.574.

Solution

Solve the equation \( 8.53x^{2}-9.81x-5.69=0 \). Solve the quadratic equation by following steps: - step0: Solve using the quadratic formula: \(8.53x^{2}-9.81x-5.69=0\) - step1: Convert the decimal into a fraction: \(\frac{853}{100}x^{2}-\frac{981}{100}x-\frac{569}{100}=0\) - step2: Multiply both sides: \(100\left(\frac{853}{100}x^{2}-\frac{981}{100}x-\frac{569}{100}\right)=100\times 0\) - step3: Calculate: \(853x^{2}-981x-569=0\) - step4: Solve using the quadratic formula: \(x=\frac{981\pm \sqrt{\left(-981\right)^{2}-4\times 853\left(-569\right)}}{2\times 853}\) - step5: Simplify the expression: \(x=\frac{981\pm \sqrt{\left(-981\right)^{2}-4\times 853\left(-569\right)}}{1706}\) - step6: Simplify the expression: \(x=\frac{981\pm \sqrt{981^{2}+1941428}}{1706}\) - step7: Separate into possible cases: \(\begin{align}&x=\frac{981+\sqrt{981^{2}+1941428}}{1706}\\&x=\frac{981-\sqrt{981^{2}+1941428}}{1706}\end{align}\) - step8: Rewrite: \(x_{1}=\frac{981-\sqrt{981^{2}+1941428}}{1706},x_{2}=\frac{981+\sqrt{981^{2}+1941428}}{1706}\) The zeros of the function \( f(x)=8.53x^{2}-9.81x-5.69 \) to three decimal places are approximately -0.424 and 1.574.

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Bonus Knowledge

To find the zeros of the quadratic function \( f(x) = 8.53 x^{2} - 9.81 x - 5.69 \), we can use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \( a = 8.53 \), \( b = -9.81 \), and \( c = -5.69 \). First, calculate the discriminant: \[ b^2 - 4ac = (-9.81)^2 - 4 \cdot 8.53 \cdot (-5.69) = 96.4561 + 193.5244 = 289.9805 \] Now, applying the quadratic formula: \[ x = \frac{-(-9.81) \pm \sqrt{289.9805}}{2 \cdot 8.53} = \frac{9.81 \pm 17.038}{17.06} \] Calculating the two possible values for \( x \): 1. \( x_1 = \frac{9.81 + 17.038}{17.06} \approx \frac{26.848}{17.06} \approx 1.576 \) 2. \( x_2 = \frac{9.81 - 17.038}{17.06} \approx \frac{-7.228}{17.06} \approx -0.424 \) Thus, the zeros of the function, rounded to three decimal places, are: \[ \boxed{1.576, -0.424} \]

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