Question
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A wall is to be supported by a wooden pole. In order for a support pole to keep a wall vertical, the angle of elevation of the pole must be within the range of \( 30-60 \) degrees. If the pole is 8 feet long, determine the distance from the base of the wall to position the pole.

Ask by Huang Collins. in Canada
Jan 21,2025

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Answer

To keep the wall vertical, place the 8-foot pole so its base is between 4 feet and approximately 6.93 feet from the wall.

Solution

To determine the appropriate distance from the base of the wall to position the 8-foot-long support pole, we can use trigonometry, specifically the cosine function. The angle of elevation (\(\theta\)) of the pole affects the horizontal distance (\(d\)) from the wall. The relationship is given by: \[ d = \text{length of pole} \times \cos(\theta) \] Given: - Length of the pole (\(L\)) = 8 feet - Angle of elevation (\(\theta\)) varies between 30° and 60° Let's calculate the distance for both extreme angles. 1. **At \(\theta = 60^\circ\):** \[ d = 8 \times \cos(60^\circ) = 8 \times 0.5 = 4 \text{ feet} \] 2. **At \(\theta = 30^\circ\):** \[ d = 8 \times \cos(30^\circ) = 8 \times \left(\frac{\sqrt{3}}{2}\right) = 4\sqrt{3} \text{ feet} \approx 6.93 \text{ feet} \] **Conclusion:** To ensure the wall remains vertical, the base of the pole should be placed at a distance between **4 feet** and **\(4\sqrt{3}\) feet** (approximately 6.93 feet) from the wall. **Final Answer:** Place the pole so its base is between 4 feet and 4 √3 feet from the wall.

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To find the distance from the base of the wall to position the 8-foot pole at angles of elevation within the range of 30 to 60 degrees, we can use trigonometric functions. For an angle of 30 degrees: \[ \text{distance} = \text{length of pole} \times \cos(30^\circ) \] Using \( \cos(30^\circ) = \sqrt{3}/2 \): \[ \text{distance} = 8 \times \frac{\sqrt{3}}{2} \approx 6.93 \text{ feet} \] For an angle of 60 degrees: \[ \text{distance} = \text{length of pole} \times \cos(60^\circ) \] Using \( \cos(60^\circ) = 1/2 \): \[ \text{distance} = 8 \times \frac{1}{2} = 4 \text{ feet} \] So the distance from the base of the wall to position the pole should be between approximately 4 feet and 6.93 feet. For a quick summary: position your pole between 4 feet and about 6.93 feet away from the wall for it to stand tall and proud!

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