A sine wave has a peak voltage of 11.5 V . What is the peak-to-peak voltage of this signal expressed in volts ?
a. 8.13 V
b. 11.50 V
c. 23.00 V
d. 7.33 V
Check

The peak-to-peak voltage of a sine wave is calculated by simply multiplying the peak voltage by 2. So, if the peak voltage is 11.5 V, the peak-to-peak voltage would be . Therefore, the answer is c. 23.00 V.

For those new to sine waves, it’s interesting to note that peak voltage represents the highest point of the wave, while peak-to-peak voltage measures the total range from the highest crest to the lowest trough! This characteristic is crucial in various applications, like audio signals and electrical systems.

When working with alternating current (AC) signals like sine waves, a common mistake is forgetting to multiply the peak voltage by two to find the peak-to-peak voltage. This can lead to confusion in calculations, especially when designing circuits or analyzing waveforms, so always remember to double-check your math!