Solve the equation by factoring $$ 16 x^{2}+2 x-3=0 $$ Rewrite the equation in factored form $$ \square=0 $$ (Factor completely )

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Solve the equation $$ 16x^2+2x-3=0 $$.
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
  $$16x^{2}+2x-3=0$$
- step1: Factor the expression:
  $$\left(2x+1ight)\left(8x-3ight)=0$$
- step2: Separate into possible cases:
  $$\begin{align}&8x-3=0\&2x+1=0\end{align}$$
- step3: Solve the equation:
  $$\begin{align}&x=\frac{3}{8}\&x=-\frac{1}{2}\end{align}$$
- step4: Rewrite:
  $$x_{1}=-\frac{1}{2},x_{2}=\frac{3}{8}$$
The equation $$16x^{2}+2x-3=0$$ can be factored as $$(8x-3)(2x+1)=0$$.
$$16x^{2}+2x-3=0$$ can be factored as $$(8x-3)(2x+1)=0$$.

Solve the equation by factoring

Rewrite the equation in factored form

(Factor completely )

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Solve the equation by factoring Rewrite the equation in factored form (Factor completely )