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Identify the domain and range of the following radical function. \( y=\sqrt[3]{x}-5 \) Domain: All Real Numbers Range: All Real Numbers Domain: \( x \geq 5 \) Range: \( y \geq 1 \) Domain: \( x \geq 0 \) Range: \( y \geq 1 \) Domain: \( x \geq 1 \) Range: \( y \geq 5 \)

Ask by Alexander Guerrero. in the United States
Feb 03,2025

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Domain: All Real Numbers Range: All Real Numbers

Solution

The function provided is: \[ y = \sqrt[3]{x} - 5 \] Let's analyze the **domain** and **range** of this function. ### Domain: A cube root function, \(\sqrt[3]{x}\), is defined for **all real numbers** because you can take the cube root of any real number (positive, negative, or zero). Subtracting 5 does not impose any additional restrictions on \(x\). - **Domain:** All Real Numbers ### Range: Since \(\sqrt[3]{x}\) can produce any real number, subtracting 5 will also yield **any real number**. There are no restrictions on the output values. - **Range:** All Real Numbers ### Conclusion: The correct identification is: - **Domain:** All Real Numbers - **Range:** All Real Numbers **Answer:** Domain: All Real Numbers Range: All Real Numbers

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The function \( y=\sqrt[3]{x}-5 \) is a radical function with a cube root, which means it can take on all real numbers for both its input (x-values) and output (y-values). Why is that? Well, cube roots can handle positive, negative, and zero values seamlessly! Therefore, the domain is indeed all real numbers, and naturally, since we can produce any real number output by adjusting \( x \), the range is also all real numbers. If you're exploring this in more depth, think about what happens if you fiddle with the 5 at the end. Shifting variations up or down in graphing play a huge role! For instance, if you added a constant instead of subtracting 5, it would raise the entire graph. Such shifts are critical in understanding transformations of functions. Having fun with those transformations can give you unique insights into behavior as you explore other functions too!

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