Solve: $$ |2 x-3| \geq 4 $$ Give your answer as an interval using whole numbers, proper fractions or improper fractions. ?

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Solve the equation $$ |2x-3| \geq 4 $$.
Solve the inequality by following steps:
- step0: Solve for $$x$$:
  $$\left|2x-3ight|\geq 4$$
- step1: Separate into possible cases:
  $$\begin{align}&2x-3\geq 4\&2x-3\leq -4\end{align}$$
- step2: Solve the inequality:
  $$\begin{align}&x\geq \frac{7}{2}\&x\leq -\frac{1}{2}\end{align}$$
- step3: Find the union:
  $$x \in \left(-\infty,-\frac{1}{2}ight]\cup \left[\frac{7}{2},+\inftyight)$$
The solution to the inequality $$|2x-3| \geq 4$$ is $$x \in (-\infty, -\frac{1}{2}) \cup (\frac{7}{2}, +\infty)$$.
The solution is $$ x \leq -\frac{1}{2} $$ or $$ x \geq \frac{7}{2} $$.

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Give your answer as an interval using whole numbers, proper fractions or improper fractions.
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Solve: Give your answer as an interval using whole numbers, proper fractions or improper fractions. ?