1) \( [2+(26 \div 2+4 \times 3)-(15 \div 3 \times 2)]+80 \div 10= \)

To find the value of the expression \( [2+(26 \div 2+4 \times 3)-(15 \div 3 \times 2)]+80 \div 10 \), we will solve it step by step following the order of operations (PEMDAS/BODMAS). 1. **Calculate inside the brackets:** - \( 26 \div 2 = 13 \) - \( 4 \times 3 = 12 \) - \( 15 \div 3 = 5 \) - So, \( 15 \div 3 \times 2 = 5 \times 2 = 10 \) Now substitute back into the expression: \[ [2 + (13 + 12) - 10] \] 2. **Continue simplifying inside the brackets:** - \( 13 + 12 = 25 \) - So, \( 2 + 25 - 10 = 17 \) Now we have: \[ [17] + 80 \div 10 \] 3. **Calculate \( 80 \div 10 \):** - \( 80 \div 10 = 8 \) 4. **Finally, add the results:** \[ 17 + 8 = 25 \] Thus, the final answer is \( \boxed{25} \).