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\( f(x)=s x^{8}+a x^{3}-5 x \) a neither b. odd e. even

Ask by Kelly Ortega. in the United States
Jan 21,2025

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函数 \( f(x) = s x^{8} + a x^{3} - 5 x \) 既不是偶函数也不是奇函数。

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函数 \( f(x) = s x^{8} + a x^{3} - 5 x \) 既不是偶函数也不是奇函数。 **选项 a. 两者都不是** **解释:** - **偶函数** 满足 \( f(-x) = f(x) \)。对于该函数: \[ f(-x) = s (-x)^{8} + a (-x)^{3} - 5 (-x) = s x^{8} - a x^{3} + 5 x \] 这与 \( f(x) \) 不相等,除非 \( a = 0 \) 且 \( 5x = -5x \),但这仅在 \( x = 0 \) 时成立,不适用于所有 \( x \)。 - **奇函数** 满足 \( f(-x) = -f(x) \)。对于该函数: \[ f(-x) = s x^{8} - a x^{3} + 5 x \] \[ -f(x) = -s x^{8} - a x^{3} + 5 x \] 要使 \( f(-x) = -f(x) \),必须 \( s = 0 \),但这限制了函数的形式,使其仅在特定条件下为奇函数。 因此,除非在特定条件下(如 \( s = 0 \) 且 \( a = 0 \)),函数 \( f(x) \) 既不是偶函数也不是奇函数。

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To determine the nature of the function \( f(x) = s x^{8} + a x^{3} - 5 x \), we can analyze its terms. The \( x^8 \) term is even, the \( x^3 \) term is odd, and the \( -5x \) term is also odd. Since there are both even and odd terms, the function itself is neither purely odd nor purely even. In general, a function is considered even if \( f(-x) = f(x) \) for all \( x \) and odd if \( f(-x) = -f(x) \). Since \( f(x) \) doesn’t satisfy either condition consistently, it fits into the "neither" category. Now, understanding the behavior of odd and even functions can be vital in many real-world applications, especially in physics, where even functions might represent systems with symmetry (like potential energy curves), while odd functions can pertain to rotational dynamics or antisymmetrical properties. Knowing how to classify functions helps streamline problem-solving—making computations with Fourier series or analyzing signals much more straightforward.

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