Solve for x $$ 25^{2 x+1}=125^{3 x+4} $$ $$ x= $$

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Solve the equation $$ 25^{2x+1}=125^{3x+4} $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$25^{2x+1}=125^{3x+4}$$
- step1: Rewrite the expression:
  $$5^{4x+2}=5^{9x+12}$$
- step2: Set the exponents equal:
  $$4x+2=9x+12$$
- step3: Move the expression to the left side:
  $$4x-9x=12-2$$
- step4: Add and subtract:
  $$-5x=12-2$$
- step5: Add and subtract:
  $$-5x=10$$
- step6: Change the signs:
  $$5x=-10$$
- step7: Divide both sides:
  $$\frac{5x}{5}=\frac{-10}{5}$$
- step8: Divide the numbers:
  $$x=-2$$
The solution to the equation $$25^{2x+1}=125^{3x+4}$$ is $$x=-2$$.
$$ x = -2 $$

Solve for x

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