Find all real zeros of the function. $$ g(x)=5(x+3)^{2}\left(x^{2}+49\right)(x-4) $$ If there is more than one answer, separate them with commas. zero(s):

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1. Factorize the function:
   $$
   g(x)=5(x+3)^2\left(x^2+49\right)(x-4)
   $$

2. Identify the zeros by setting each factor equal to zero:
   - For the factor $$(x+3)^2$$:
     $$
     x+3=0 \quad \Longrightarrow \quad x=-3
     $$
     
   - For the factor $$x^2+49$$:
     $$
     x^2+49=0 \quad \Longrightarrow \quad x^2=-49
     $$
     Since $$x^2=-49$$ has no real solutions, no real zero comes from this factor.
     
   - For the factor $$(x-4)$$:
     $$
     x-4=0 \quad \Longrightarrow \quad x=4
     $$

3. The real zeros of the function are:
   $$
   -3,\, 4
   $$
The real zeros are -3 and 4.

Find all real zeros of the function.

If there is more than one answer, separate them with commas.
zero(s):

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Find all real zeros of the function. If there is more than one answer, separate them with commas. zero(s):