Express your answer as a polynomial in standard form. \[ \begin{array}{r}f(x)=2 x^{2}-x+6 \\ g(x)=2 x+12 \\ \text { Find: } g(f(x))\end{array} \]

To find \( g(f(x)) \), we first need to substitute \( f(x) \) into \( g(x) \). Given: \[ f(x) = 2x^2 - x + 6 \] \[ g(x) = 2x + 12 \] Now, we substitute \( f(x) \) into \( g(x) \): \[ g(f(x)) = g(2x^2 - x + 6) \] Now, replace \( x \) in \( g(x) \) with \( f(x) \): \[ g(f(x)) = 2(2x^2 - x + 6) + 12 \] Next, we distribute the 2: \[ = 4x^2 - 2x + 12 + 12 \] Now, combine the constant terms: \[ = 4x^2 - 2x + 24 \] Putting this in standard form (which is already arranged from highest degree to lowest degree), we get: \[ \boxed{4x^2 - 2x + 24} \]