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(38) \( \frac{\frac{2 r+10}{r^{2}}}{\frac{r^{2}-25}{4 r}} \)

Ask by French Vaughan. in the United States
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\[ \frac{8}{r(r - 5)} \]

Solution

To simplify the expression: \[ \frac{\frac{2r + 10}{r^2}}{\frac{r^2 - 25}{4r}} \] **Step 1: Rewrite the Division as Multiplication** \[ \frac{2r + 10}{r^2} \div \frac{r^2 - 25}{4r} = \frac{2r + 10}{r^2} \times \frac{4r}{r^2 - 25} \] **Step 2: Factor Where Possible** - Factor \(2r + 10\): \[ 2r + 10 = 2(r + 5) \] - Factor \(r^2 - 25\) (difference of squares): \[ r^2 - 25 = (r + 5)(r - 5) \] **Step 3: Substitute the Factors Back Into the Expression** \[ \frac{2(r + 5)}{r^2} \times \frac{4r}{(r + 5)(r - 5)} \] **Step 4: Cancel Common Factors** - The \((r + 5)\) terms cancel out: \[ \frac{2}{r^2} \times \frac{4r}{r - 5} \] **Step 5: Multiply the Remaining Terms** \[ \frac{2 \times 4r}{r^2 (r - 5)} = \frac{8r}{r^2 (r - 5)} \] **Step 6: Simplify the Expression** \[ \frac{8r}{r^2 (r - 5)} = \frac{8}{r (r - 5)} \] **Final Simplified Form:** \[ \boxed{\dfrac{8}{\,r(r-5)\,}} \]

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The Deep Dive

To simplify \( \frac{\frac{2 r+10}{r^{2}}}{\frac{r^{2}-25}{4 r}} \), we first need to rewrite the expression as multiplication by the reciprocal of the denominator: \[ = \frac{2r + 10}{r^2} \cdot \frac{4r}{r^2 - 25} \] Next, factor the numerator \( 2r + 10 \) and the denominator \( r^2 - 25 \): \[ 2r + 10 = 2(r + 5) \] \[ r^2 - 25 = (r - 5)(r + 5) \] Now we can substitute these factors back into the expression: \[ = \frac{2(r + 5)}{r^2} \cdot \frac{4r}{(r - 5)(r + 5)} \] Next, we can cancel \( (r + 5) \) from the numerator and the denominator (assuming \( r \neq -5 \)): \[ = \frac{2 \cdot 4r}{r^2 (r - 5)} = \frac{8r}{r^2(r - 5)} = \frac{8}{r(r - 5)} \quad \text{(assuming } r \neq 0\text{)} \] Thus, the simplified expression is: \[ \frac{8}{r(r - 5)} \] This is the final result.

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