A rectangular room is 6 meters longer than it is wide, and its perimeter is 28 meters. Find the dimension of the room. The length is: meters and the width is

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Let's solve the problem step by step.

**Given:**
- The length of the room is 6 meters longer than its width.
- The perimeter of the room is 28 meters.

**Let's define:**
- Let $$ w $$ be the width of the room in meters.
- Then, the length $$ l $$ is $$ w + 6 $$ meters.

**Perimeter of a rectangle** is calculated by the formula:
$$
\text{Perimeter} = 2 \times (\text{Length} + \text{Width})
$$

Plugging the known values into the formula:
$$
2 \times (l + w) = 28
$$
$$
2 \times ((w + 6) + w) = 28
$$
$$
2 \times (2w + 6) = 28
$$
$$
4w + 12 = 28
$$
$$
4w = 28 - 12
$$
$$
4w = 16
$$
$$
w = \frac{16}{4}
$$
$$
w = 4 \text{ meters}
$$

Now, find the length:
$$
l = w + 6 = 4 + 6 = 10 \text{ meters}
$$

**Answer:**
- **Length:** 10 meters
- **Width:** 4 meters
The room is 10 meters long and 4 meters wide.

A rectangular room is 6 meters longer than it is wide, and its perimeter is 28 meters. Find the dimension of the room. The length is: meters and the width is

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