Solve using the Quadratic Formula. $$ \begin{array}{l}6 x^{2}+7 x-5=0 \ x=\frac{-7 \pm i \sqrt{71}}{12} \ x=-\frac{1}{2} ext { and } x=\frac{5}{3} \ x=\frac{-7 \pm i \sqrt{71}}{2} \ x=\frac{1}{2} ext { and } x=-\frac{5}{3}\end{array} $$

Question

Solve using the Quadratic Formula. $$ \begin{array}{l}6 x^{2}+7 x-5=0 \ x=\frac{-7 \pm i \sqrt{71}}{12} \ x=-\frac{1}{2} 	ext { and } x=\frac{5}{3} \ x=\frac{-7 \pm i \sqrt{71}}{2} \ x=\frac{1}{2} 	ext { and } x=-\frac{5}{3}\end{array} $$

UpStudy AI · Accepted Answer

Solve the equation $$ 6x^2+7x-5=0 $$.
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
  $$6x^{2}+7x-5=0$$
- step1: Factor the expression:
  $$\left(2x-1ight)\left(3x+5ight)=0$$
- step2: Separate into possible cases:
  $$\begin{align}&2x-1=0\&3x+5=0\end{align}$$
- step3: Solve the equation:
  $$\begin{align}&x=\frac{1}{2}\&x=-\frac{5}{3}\end{align}$$
- step4: Rewrite:
  $$x_{1}=-\frac{5}{3},x_{2}=\frac{1}{2}$$
The solutions to the quadratic equation $$6x^{2}+7x-5=0$$ using the Quadratic Formula are $$x=-\frac{5}{3}$$ and $$x=\frac{1}{2}$$.
The solutions are $$x=-\frac{5}{3}$$ and $$x=\frac{1}{2}$$.

Solve using the Quadratic Formula.

Upstudy AI Solution

Answer

Solution

Bonus Knowledge

Related Questions

Latest Algebra Questions