Find the slope and $$ y $$-intercept of the line. (If an answer does not exist, enter DNE.) $$ 5 x+6 y=12 $$ slope $$ y $$-intercept $$ \quad(x, y)=(\square $$

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To find the **slope** and **$$ y $$-intercept** of the line given by the equation:

$$ 5x + 6y = 12 $$

**1. Solve for $$ y $$ in terms of $$ x $$ to get the equation in slope-intercept form ($$ y = mx + b $$):**

$$
\begin{align*}
5x + 6y &= 12 \
6y &= -5x + 12 \
y &= -\frac{5}{6}x + 2
\end{align*}
$$

**2. Identify the slope ($$ m $$) and $$ y $$-intercept ($$ b $$):**

- **Slope ($$ m $$)**: The coefficient of $$ x $$ is $$ -\frac{5}{6} $$.
  
  $$
  \text{Slope} = -\frac{5}{6}
  $$

- **$$ y $$-intercept ($$ b $$)**: The constant term is $$ 2 $$, which corresponds to the point $$ (0, 2) $$ on the graph.
  
  $$
  \text{$$ y $$-intercept} = (0, 2)
  $$

**Final Answer:**

- **Slope:** $$ -\dfrac{5}{6} $$
- **$$ y $$-intercept:** $$ (0,\ 2) $$
Slope: $$-\dfrac{5}{6}$$, $$ y $$-intercept: $$ (0,\ 2) $$

Find the slope and -intercept of the line. (If an answer does not exist, enter DNE.)

slope
-intercept

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Find the slope and -intercept of the line. (If an answer does not exist, enter DNE.) slope -intercept