6) \( \begin{aligned} 6 x+6 y & =-6 \\ -2 x-3 y & =-3\end{aligned} \)
Real Tutor Solution
Answer
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Bonus Knowledge
To solve the system of equations \( 6x + 6y = -6 \) and \( -2x - 3y = -3 \), we can start by simplifying both equations. Dividing the first equation by 6 gives us \( x + y = -1 \) or \( y = -1 - x \). For the second equation, dividing by -1 yields \( 2x + 3y = 3 \). Now, substituting \( y = -1 - x \) into the second equation: \[ 2x + 3(-1 - x) = 3 \] \[ 2x - 3 - 3x = 3 \] \[ -1x - 3 = 3 \] \[ -1x = 6 \implies x = -6 \] Now substituting \( x = -6 \) back into \( y = -1 - x \): \[ y = -1 - (-6) = -1 + 6 = 5 \] Thus, the solution to the system of equations is \( x = -6 \) and \( y = 5 \). Let's express them in coordinate form: The solution is the point \( (-6, 5) \).