Question
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a) \( \frac{3 x-2 x-1}{2^{x}+2^{x}+9} \)

Ask by Harper Chan. in South Africa
Jan 22,2025

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Tutor-Verified Answer

Answer

\[ \frac{x - 1}{2^{x+1} + 9} \]

Solution

Certainly! Let's simplify the given expression step by step. **Given Expression:** \[ \frac{3x - 2x - 1}{2^{x} + 2^{x} + 9} \] **Step 1: Simplify the Numerator** Combine like terms in the numerator: \[ 3x - 2x - 1 = (3x - 2x) - 1 = x - 1 \] **Step 2: Simplify the Denominator** Combine like terms in the denominator: \[ 2^{x} + 2^{x} + 9 = 2 \cdot 2^{x} + 9 \] Recall that \(2 \cdot 2^{x} = 2^{x+1}\). So, \[ 2 \cdot 2^{x} + 9 = 2^{x+1} + 9 \] **Step 3: Write the Simplified Expression** Putting it all together: \[ \frac{x - 1}{2^{x+1} + 9} \] **Final Simplified Form:** \[ \frac{x - 1}{2^{x+1} + 9} \]

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Mind Expander

To simplify the given expression, let's start with the numerator: \(3x - 2x - 1\) simplifies to \(x - 1\). Next, for the denominator \(2^x + 2^x + 9\), notice that \(2^x + 2^x\) is equivalent to \(2 \times 2^x\) or simply \(2^{x+1}\). So, the complete expression can be rewritten as: \[ \frac{x - 1}{2^{x+1} + 9} \] And there you have it, simplified without losing the essence of the original!

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