Question
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Find the least common multiple. \( 4 r^{6}, 14 r^{9} \) Write your answer as a constant times a product of single variables raised to exponents.

Ask by Bird Garza. in the United States
Jan 22,2025

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Answer

The least common multiple of \( 4r^{6} \) and \( 14r^{9} \) is \( 28r^{9} \).

Solution

To find the least common multiple (LCM) of the monomials \( 4r^{6} \) and \( 14r^{9} \), follow these steps: 1. **Factor the coefficients into their prime factors:** - \( 4 = 2^2 \) - \( 14 = 2 \times 7 \) 2. **Determine the LCM of the coefficients:** - Take the highest power of each prime factor present. - \( \text{LCM}(4, 14) = 2^2 \times 7 = 28 \) 3. **Determine the LCM of the variable parts:** - Take the highest exponent of \( r \) present in both terms. - \( \text{LCM}(r^6, r^9) = r^9 \) 4. **Combine the LCM of the coefficients and the variable parts:** - \( \text{LCM}(4r^{6}, 14r^{9}) = 28r^{9} \) **Final Answer:** \( 28\, r^{9} \)

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To find the least common multiple (LCM) of \( 4r^6 \) and \( 14r^9 \), we first determine the LCM of the coefficients and the LCM of the variable terms separately. The coefficients are 4 and 14. The prime factorization of 4 is \( 2^2 \) and for 14 is \( 2^1 \times 7^1 \). The LCM takes the highest power of each prime factor: - For 2, the highest power is \( 2^2 \). - For 7, the highest power is \( 7^1 \). Thus, the LCM of the coefficients is \( 2^2 \times 7^1 = 4 \times 7 = 28 \). For the variable \( r \), we take the highest exponent from the two terms: - \( r^6 \) and \( r^9 \) gives us \( r^9 \). Combining these results, the LCM of \( 4r^6 \) and \( 14r^9 \) is: \[ 28r^9 \] And there you have it—the least common multiple is \( 28r^9 \)!

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