Question
b) \( 412 \times 1 \) d) \( (25 \div 1)+(102 \times 0) \)
Ask by Alexander Ross. in South Africa
Jan 23,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\( 412 \times 1 = 412 \)
\( (25 \div 1) + (102 \times 0) = 25 \)
Solution
Certainly! Let's evaluate each expression step by step.
---
**b) \( 412 \times 1 \)**
Multiplying any number by 1 gives the original number.
\[
412 \times 1 = 412
\]
**Answer:** \( 412 \)
---
**d) \( (25 \div 1) + (102 \times 0) \)**
Let's break it down:
1. **Division:**
\[
25 \div 1 = 25
\]
2. **Multiplication:**
\[
102 \times 0 = 0
\]
3. **Addition:**
\[
25 + 0 = 25
\]
**Answer:** \( 25 \)
---
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Simplify this solution The Deep Dive
Did you know that multiplying any number by 1 gives you that same number? It’s a funky little rule in math that helps keep things simple! So, \( 412 \times 1 = 412 \). Easy peasy, right? Now, let's dive into the second expression! When you divide any number by 1, it also stays the same. And multiplying by 0 always gives you 0! So, in \( (25 \div 1) + (102 \times 0) \), you get \( 25 + 0 = 25 \). Math magic at its finest!
