Find the zeros $$ (x $$-intercepts) of $$ p(x)=(x+1)(x+2)(9 x+4) $$ The zeros are $$ x=\square $$ Separate answers with commas as necessary.

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The polynomial $$ p(x) = (x+1)(x+2)(9x+4) $$ is already factored. To find the zeros, we need to set each factor equal to zero.
1. $$ x + 1 = 0 $$
2. $$ x + 2 = 0 $$
3. $$ 9x + 4 = 0 $$

Now, we will solve each equation for $$ x $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$x+1=0$$
- step1: Move the constant to the right side:
  $$x=0-1$$
- step2: Remove 0:
  $$x=-1$$
Solve the equation $$ x+2=0 $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$x+2=0$$
- step1: Move the constant to the right side:
  $$x=0-2$$
- step2: Remove 0:
  $$x=-2$$
Solve the equation $$ 9x+4=0 $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$9x+4=0$$
- step1: Move the constant to the right side:
  $$9x=0-4$$
- step2: Remove 0:
  $$9x=-4$$
- step3: Divide both sides:
  $$\frac{9x}{9}=\frac{-4}{9}$$
- step4: Divide the numbers:
  $$x=-\frac{4}{9}$$
The zeros (x-intercepts) of $$ p(x) = (x+1)(x+2)(9x+4) $$ are $$ x = -1, -2, -\frac{4}{9} $$.

Find the zeros -intercepts) of
The zeros are
Separate answers with commas as necessary.

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Find the zeros -intercepts) of The zeros are Separate answers with commas as necessary.