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My IXL Learning Assessment Analytics ade \( > \) cc. 1 Evaluate a linear function LNV 4) Use the function \( d=h+11 \) to find the value of \( d \) when \( h=1 \). Submit

Ask by Herrera Erickson. in the United States
Jan 23,2025

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When \( h = 1 \), \( d = 12 \).

Solution

Sure, I'd be happy to help you solve this problem! **Problem:** Use the function \( d = h + 11 \) to find the value of \( d \) when \( h = 1 \). **Solution:** 1. **Understand the Function:** - The function \( d = h + 11 \) is a linear function where: - \( d \) depends on the value of \( h \). - For every increase in \( h \), \( d \) increases by the same amount since the function has a slope of 1. 2. **Substitute the Given Value into the Function:** - You are given \( h = 1 \). - Plug this value into the function: \[ d = h + 11 \] \[ d = 1 + 11 \] 3. **Calculate the Value of \( d \):** \[ d = 1 + 11 = 12 \] **Answer:** When \( h = 1 \), the value of \( d \) is **12**.

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With the function \( d = h + 11 \), substituting \( h = 1 \) gives us \( d = 1 + 11 = 12 \). So, when \( h \) is 1, the value of \( d \) is 12. Linear functions are super easy to work with! Just remember, the general format is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. If you know a point on the line and the slope, you can find any other point on that line just as easily!

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