14) $$ \frac{3 x^{6} y^{8} z^{5}}{2 x^{8} y^{5} z^{7} \cdot-8 z x^{-4} \cdot-4 x y^{0} z^{0}} $$

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To simplify the expression:

$$
\frac{3 x^{6} y^{8} z^{5}}{2 x^{8} y^{5} z^{7} \cdot -8 z x^{-4} \cdot -4 x y^{0} z^{0}}
$$

**Step 1: Simplify the Denominator**

First, simplify each part of the denominator:

1. $$ y^{0} = 1 $$ and $$ z^{0} = 1 $$, so the third term becomes:
   $$
   -4x \cdot 1 \cdot 1 = -4x
   $$

2. Multiply the constants and like variables in the denominator:
   $$
   2 x^{8} y^{5} z^{7} \cdot (-8 z x^{-4}) \cdot (-4x) 
   $$
   
   - **Constants**: $$ 2 \times (-8) \times (-4) = 64 $$
   
   - **Variables**:
     $$
     x^{8} \cdot x^{-4} \cdot x = x^{8-4+1} = x^{5}
     $$
     $$
     y^{5} \cdot 1 = y^{5}
     $$
     $$
     z^{7} \cdot z \cdot 1 = z^{8}
     $$
   
   So, the denominator simplifies to:
   $$
   64 x^{5} y^{5} z^{8}
   $$

**Step 2: Simplify the Entire Fraction**

Now, write the entire expression with the simplified denominator:
$$
\frac{3 x^{6} y^{8} z^{5}}{64 x^{5} y^{5} z^{8}}
$$

Subtract the exponents for each variable:

- **For $$ x $$**:
  $$
  x^{6-5} = x^{1} = x
  $$
  
- **For $$ y $$**:
  $$
  y^{8-5} = y^{3}
  $$
  
- **For $$ z $$**:
  $$
  z^{5-8} = z^{-3} = \frac{1}{z^{3}}
  $$

**Final Simplified Form:**
$$
\frac{3x y^{3}}{64 z^{3}}
$$

**Answer:**
$$
\frac{3\, x\, y^{3}}{64\, z^{3}}
$$
$$ \frac{3x y^{3}}{64 z^{3}} $$

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