Complete the equation \( \begin{array}{r}9 \frac{1}{3} \quad 8+\frac{3}{3}+\frac{1}{3} \\ -3 \frac{2}{3}-3 \frac{2}{3}\end{array} \)

To complete the equation, we need to perform the calculations step by step. 1. **Convert mixed numbers to improper fractions:** - For \(9 \frac{1}{3}\): \[ 9 \frac{1}{3} = \frac{9 \times 3 + 1}{3} = \frac{27 + 1}{3} = \frac{28}{3} \] - For \(3 \frac{2}{3}\): \[ 3 \frac{2}{3} = \frac{3 \times 3 + 2}{3} = \frac{9 + 2}{3} = \frac{11}{3} \] 2. **Rewrite the equation:** The equation now looks like this: \[ \begin{array}{r} \frac{28}{3} + 8 + \frac{3}{3} + \frac{1}{3} \\ - \frac{11}{3} - \frac{11}{3} \end{array} \] 3. **Combine the fractions:** - First, simplify \(8 + \frac{3}{3} + \frac{1}{3}\): \[ 8 + \frac{3}{3} + \frac{1}{3} = 8 + 1 + \frac{1}{3} = 9 + \frac{1}{3} = \frac{27}{3} + \frac{1}{3} = \frac{28}{3} \] 4. **Now, combine everything:** \[ \frac{28}{3} + \frac{28}{3} - \frac{11}{3} - \frac{11}{3} \] 5. **Calculate the total:** - Combine the first two terms: \[ \frac{28}{3} + \frac{28}{3} = \frac{56}{3} \] - Combine the last two terms: \[ -\frac{11}{3} - \frac{11}{3} = -\frac{22}{3} \] - Now combine these results: \[ \frac{56}{3} - \frac{22}{3} = \frac{56 - 22}{3} = \frac{34}{3} \] Thus, the completed equation results in: \[ \frac{34}{3} \]