Complete the equation \( \begin{array}{r}9 \frac{1}{3} \quad 8+\frac{3}{3}+\frac{1}{3} \\ -3 \frac{2}{3}-3 \frac{2}{3}\end{array} \)

To complete the equation, we first convert the mixed numbers into improper fractions and perform the calculations. The first term, \(9 \frac{1}{3}\), can be converted as follows: \[ 9 \frac{1}{3} = \frac{28}{3} \] Now let's add the second part of the equation: \[ 8 + \frac{3}{3} + \frac{1}{3} = 8 + 1 + \frac{1}{3} = 9 + \frac{1}{3} = \frac{28}{3} + \frac{1}{3} = \frac{29}{3} \] Now we calculate the entire first part: \[ \frac{28}{3} + \frac{29}{3} = \frac{57}{3} \] Next, we compute the second part: Both terms, \( -3 \frac{2}{3} \), convert to: \[ -3 \frac{2}{3} = -\frac{11}{3} \] So, \[ -\frac{11}{3} - \frac{11}{3} = -\frac{22}{3} \] Now we put it all together: \[ \frac{57}{3} - \frac{22}{3} = \frac{57 - 22}{3} = \frac{35}{3} \] Thus, the completed equation results in: \[ \frac{35}{3} \] or \(11 \frac{2}{3}\).