Question
\( \frac{c+d}{3 x} \cdot \frac{63}{5(c+d)}=\square \) (Simplify your answer.)
Ask by Schwartz Gough. in the United States
Jan 21,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\[
\frac{21}{5x}
\]
Solution
To simplify the expression:
\[
\frac{c+d}{3x} \cdot \frac{63}{5(c+d)}
\]
1. **Cancel Common Terms:**
The \((c + d)\) terms in the numerator and denominator cancel each other out (assuming \(c + d \neq 0\)):
\[
\frac{1}{3x} \cdot \frac{63}{5}
\]
2. **Multiply the Remaining Fractions:**
\[
\frac{63}{3x \cdot 5} = \frac{63}{15x}
\]
3. **Simplify the Fraction:**
Divide both the numerator and the denominator by 3:
\[
\frac{21}{5x}
\]
**Final Simplified Answer:**
\[
\frac{21}{5x}
\]
Reviewed and approved by the UpStudy tutoring team
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Mind Expander
To simplify the given expression \( \frac{c+d}{3 x} \cdot \frac{63}{5(c+d)} \), we first notice that \( c+d \) in the numerator and denominator cancels out: \[ = \frac{1}{3 x} \cdot \frac{63}{5} \] Now, multiply the constants: \[ = \frac{63}{15 x} \] Next, we can simplify \( \frac{63}{15} \) by dividing both the numerator and the denominator by 3: \[ = \frac{21}{5 x} \] Therefore, the simplified expression is: \[ \frac{21}{5 x} \]