Question
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\( \frac{c+d}{3 x} \cdot \frac{63}{5(c+d)}=\square \) (Simplify your answer.)

Ask by Schwartz Gough. in the United States
Jan 21,2025

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Tutor-Verified Answer

Answer

\[ \frac{21}{5x} \]

Solution

To simplify the expression: \[ \frac{c+d}{3x} \cdot \frac{63}{5(c+d)} \] 1. **Cancel Common Terms:** The \((c + d)\) terms in the numerator and denominator cancel each other out (assuming \(c + d \neq 0\)): \[ \frac{1}{3x} \cdot \frac{63}{5} \] 2. **Multiply the Remaining Fractions:** \[ \frac{63}{3x \cdot 5} = \frac{63}{15x} \] 3. **Simplify the Fraction:** Divide both the numerator and the denominator by 3: \[ \frac{21}{5x} \] **Final Simplified Answer:** \[ \frac{21}{5x} \]

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Mind Expander

To simplify the given expression \( \frac{c+d}{3 x} \cdot \frac{63}{5(c+d)} \), we first notice that \( c+d \) in the numerator and denominator cancels out: \[ = \frac{1}{3 x} \cdot \frac{63}{5} \] Now, multiply the constants: \[ = \frac{63}{15 x} \] Next, we can simplify \( \frac{63}{15} \) by dividing both the numerator and the denominator by 3: \[ = \frac{21}{5 x} \] Therefore, the simplified expression is: \[ \frac{21}{5 x} \]

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