Robert leans a $$ 20- $$ foot ladder against a wall. If the ladder reaches 19.2 feet up the wall, what angle does form with the wall? Round your answer to the nearest tenth of a degree.

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To determine the angle that the ladder forms with the wall, we can use trigonometric relationships in a right triangle.

**Given:**
- **Ladder length (hypotenuse):** 20 feet
- **Height up the wall (adjacent side):** 19.2 feet

**Objective:**
Find the angle $$ \theta $$ between the ladder and the wall.

**Using the cosine function:**
$$
\cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{19.2}{20} = 0.96
$$

To find $$ \theta $$, take the inverse cosine (arccos) of 0.96:
$$
\theta = \cos^{-1}(0.96)
$$

Calculating this:
$$
\theta \approx 16.0^\circ
$$

**Conclusion:**
The ladder forms an angle of **16.0 degrees** with the wall when rounded to the nearest tenth of a degree.

**Answer:**  
The angle is approximately 16.0 degrees.
The angle between the ladder and the wall is approximately 16.0 degrees.

Robert leans a foot ladder against a wall. If the ladder reaches 19.2 feet up the wall, what angle does
form with the wall? Round your answer to the nearest tenth of a degree.

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Robert leans a foot ladder against a wall. If the ladder reaches 19.2 feet up the wall, what angle does form with the wall? Round your answer to the nearest tenth of a degree.