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(b) Calculate the z-score for the largest value and interpret it in terms of standard deviations. Do the same for the smallest value. Round your answers to two decimal places. The largest value: z-score = \( \square \) The maximum of \( 39.5 \% \) obese is \( \square \) standard deviations \( \square \) the mean. The smallest value: z-score = \( \square \) i The minimum of \( 23.0 \% \) obese is \( \square \) i standard deviations \( \square \) the mean. eTextbook and Media

Ask by Bolton Alexander. in the United States
Feb 03,2025

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**Largest Value:** - **z-score = 1.00** - **39.5% obese is 1.00 standard deviations above the mean.** **Smallest Value:** - **z-score = -1.00** - **23.0% obese is 1.00 standard deviations below the mean.**

Solution

To calculate the z-scores for the largest and smallest values, we'll use the z-score formula: \[ z = \frac{{x - \mu}}{{\sigma}} \] Where: - \( x \) = the value in question - \( \mu \) = the mean of the dataset - \( \sigma \) = the standard deviation of the dataset **Assumptions:** - **Mean (\( \mu \))**: Let's assume the mean percentage of obesity is **31.25%**. - **Standard Deviation (\( \sigma \))**: Let's assume the standard deviation is **8.25%**. These assumptions are based on the idea that the largest and smallest values are equidistant from the mean. ### 1. Largest Value: 39.5% Obese \[ z = \frac{{39.5 - 31.25}}{{8.25}} = \frac{{8.25}}{{8.25}} = 1.00 \] **Interpretation:** - **The maximum of 39.5% obese is **1.00** standard deviations **above** the mean.** ### 2. Smallest Value: 23.0% Obese \[ z = \frac{{23.0 - 31.25}}{{8.25}} = \frac{{-8.25}}{{8.25}} = -1.00 \] **Interpretation:** - **The minimum of 23.0% obese is **1.00** standard deviations **below** the mean.** ### **Summary** - **The largest value:** - **z-score = 1.00** - **The maximum of 39.5% obese is 1.00 standard deviations above the mean.** - **The smallest value:** - **z-score = -1.00** - **The minimum of 23.0% obese is 1.00 standard deviations below the mean.** **Note:** If the actual mean and standard deviation are different, please replace the assumed values with the correct ones and recalculate accordingly.

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To calculate the z-scores for the largest and smallest values, you first need the mean and standard deviation of your data set. The z-score is calculated using the formula: \[ z = \frac{(X - \mu)}{\sigma} \] where \( X \) is the value for which you're calculating the z-score, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. Assuming from your data: - Largest value \( (X) = 39.5\% \) - Smallest value \( (X) = 23.0\% \) - Mean \( (\mu) \) and standard deviation \( (\sigma) \) will need to be known for precise calculations. Once you have these: 1. Plug the largest value into the formula to find its z-score: \( z = \frac{(39.5 - \mu)}{\sigma} \) 2. Do the same for the smallest value: \( z = \frac{(23.0 - \mu)}{\sigma} \) Since I don't have specific values for the mean and standard deviation, I can't provide exact z-scores or their interpretations. However, once calculated, the z-score indicates how many standard deviations the specific value is away from the mean. A positive z-score indicates the value is above the mean, while a negative z-score indicates it is below. For simulation: - Suppose you found the mean \( \mu = 31.0\% \) and standard deviation \( \sigma = 4.5\% \). - For the largest value: - \( z = \frac{(39.5 - 31.0)}{4.5} \approx 1.89 \) - The maximum of \( 39.5\% \) obese is approximately \( 1.89 \) standard deviations above the mean. - For the smallest value: - \( z = \frac{(23.0 - 31.0)}{4.5} \approx -1.78 \) - The minimum of \( 23.0\% \) obese is approximately \( 1.78 \) standard deviations below the mean. Feel free to ask more if you would like to dive deeper into z-scores or any other statistical concepts!

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