Solve for \( y \). \[ -\frac{4}{7} y+\frac{4}{3}=-\frac{1}{6} \] Simplify your answer as much as possible \( y=\square \)
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The Deep Dive
To solve the equation \[ -\frac{4}{7} y + \frac{4}{3} = -\frac{1}{6}, \] we will first isolate \( y \). Start by moving \( \frac{4}{3} \) to the right side: \[ -\frac{4}{7} y = -\frac{1}{6} - \frac{4}{3}. \] Next, we need a common denominator to combine the fractions on the right side. The least common multiple of 6 and 3 is 6. Rewrite \( \frac{4}{3} \) with a denominator of 6: \[ \frac{4}{3} = \frac{4 \times 2}{3 \times 2} = \frac{8}{6}. \] Now substitute this back in: \[ -\frac{4}{7} y = -\frac{1}{6} - \frac{8}{6} = -\frac{9}{6}. \] We can simplify \( -\frac{9}{6} \): \[ -\frac{9}{6} = -\frac{3}{2}. \] Now we have: \[ -\frac{4}{7} y = -\frac{3}{2}. \] To solve for \( y \), multiply both sides by \( -\frac{7}{4} \) (the reciprocal of \(-\frac{4}{7}\)): \[ y = -\frac{3}{2} \times -\frac{7}{4} = \frac{3 \times 7}{2 \times 4} = \frac{21}{8}. \] Thus, the solution is: \[ y = \frac{21}{8}. \]