Solve for the roots in simplest form by completing the square: \[ -5 x^{2}-10 x-50=0 \]
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The Deep Dive
To solve for the roots of the equation \(-5 x^{2}-10 x-50=0\) by completing the square, we first divide every term by -5: \[ x^{2} + 2x + 10 = 0 \] Next, we isolate the constant term: \[ x^{2} + 2x = -10 \] Now, we complete the square by taking half of the coefficient of \(x\) (which is 2), squaring it, and adding it to both sides: \[ x^{2} + 2x + 1 = -10 + 1 \] This simplifies to: \[ (x + 1)^{2} = -9 \] Since the right side is negative, we can take the square root of both sides: \[ x + 1 = \pm 3i \] Now, we isolate \(x\) by subtracting 1 from both sides: \[ x = -1 \pm 3i \] Thus, the roots in simplest form are: \[ x = -1 + 3i \quad \text{and} \quad x = -1 - 3i \]