Select the product $$ (4+i)(-2-i) $$ in the standard form $$ a+b i $$. a.) $$ -8-i^{2} $$ b.) $$ 8-i^{2} $$ c.) $$ 7-6 i $$ d.) $$ -7-6 i $$

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Calculate or simplify the expression $$ (4+i)(-2-i) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\left(4+i\right)\left(-2-i\right)$$
- step1: Apply the distributive property:
  $$4\left(-2\right)+4\left(-i\right)+i\left(-2\right)+i\left(-i\right)$$
- step2: Multiply the numbers:
  $$-8+4\left(-i\right)+i\left(-2\right)+i\left(-i\right)$$
- step3: Multiply the numbers:
  $$-8-4i+i\left(-2\right)+i\left(-i\right)$$
- step4: Multiply the numbers:
  $$-8-4i-2i+i\left(-i\right)$$
- step5: Multiply the numbers:
  $$-8-4i-2i+1$$
- step6: Calculate:
  $$-7-4i-2i$$
- step7: Multiply the numbers:
  $$-7-6i$$
The product $$ (4+i)(-2-i) $$ in the standard form $$ a+bi $$ is $$ -7-6i $$.

Therefore, the correct answer is d.) $$ -7-6i $$.
The product is $$ -7-6i $$.

Select the product in the standard form .
a.)
b.)
c.)
d.)

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