Summary work \#5 Option I 1. The area of the triangle \( A B C \) is 10 cm 2, and the length of the side \( A B \) is 5 cm . Calculate the length of the allowed height on the side \( A B \). 2. The perimeter of a rhombus is 40 cm , and the product of the lengths of the diagonals is 192 cm . Calculate the height of the rhombus:
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To find the height of triangle \( ABC \), we can use the formula for the area of a triangle, which is \( A = \frac{1}{2} \times \text{base} \times \text{height} \). Here, the area is 10 cm² and the base \( AB \) is 5 cm. Rearranging the formula gives us the height \( h = \frac{2A}{\text{base}} = \frac{2 \times 10}{5} = 4 \) cm. So, the allowed height on side \( AB \) is 4 cm. For the rhombus, the perimeter \( P \) is given by \( P = 4a \) where \( a \) is the length of a side. Given \( P = 40 \) cm, we find \( a = 10 \) cm. The height \( h \) can be calculated using the formula for the area of a rhombus, \( A = \frac{1}{2} \times d_1 \times d_2 \). However, since we know the lengths of the diagonals multiply to 192, we can express them as \( d_1 = \frac{192}{d_2} \) and substitute into the formula for area. The height can then be found using \( h = \frac{A}{a} \) for the rhombus, leading to a height calculation of approximately 7.68 cm.