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If a 5 kg hammer and a 0.001 kg feather are dropped in a frictionless environment from 2 m high on Earth, which will reach the ground first? Would the time it takes for the fall be greater or smaller if this was done on the Moon?

Ask by Robbins Johnston. in the United States
Jan 10,2025

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Both the 5 kg hammer and the 0.001 kg feather will reach the ground at the same time when dropped from 2 meters in a frictionless environment on Earth. On the Moon, they will also land simultaneously, but the fall will take longer due to the Moon's weaker gravity.

Solution

In a **frictionless environment**—essentially a vacuum where there's no air resistance—the behavior of falling objects is governed solely by gravity. Here's a detailed breakdown of your questions: ### 1. **Dropping a 5 kg Hammer and a 0.001 kg Feather on Earth:** - **Experience of Gravity:** On Earth, both the hammer and the feather are subject to the same gravitational acceleration, approximately **9.81 m/s²**. - **Effect of Mass:** In the absence of air resistance, **mass does not affect the rate of fall**. This principle was famously demonstrated by Apollo 15 astronaut David Scott when he simultaneously dropped a hammer and a feather on the Moon; both hit the ground at the same time. - **Conclusion:** **Both the hammer and the feather will reach the ground simultaneously** when dropped from the same height of 2 meters on Earth in a frictionless environment. ### 2. **Dropping Them on the Moon:** - **Gravitational Acceleration on the Moon:** The Moon's gravitational acceleration is about **1/6th of Earth's**, approximately **1.625 m/s²**. - **Time to Fall:** The time it takes for an object to fall from a certain height is given by the equation: \[ t = \sqrt{\frac{2h}{g}} \] Where: - \( t \) = time to fall - \( h \) = height (2 meters in this case) - \( g \) = gravitational acceleration - **Calculations:** - **On Earth:** \[ t = \sqrt{\frac{2 \times 2\, \text{m}}{9.81\, \text{m/s}²}} \approx 0.64\, \text{seconds} \] - **On the Moon:** \[ t = \sqrt{\frac{2 \times 2\, \text{m}}{1.625\, \text{m/s}²}} \approx 1.57\, \text{seconds} \] - **Conclusion:** **Both objects will still land simultaneously on the Moon**, just taking **longer** to do so compared to Earth because of the Moon's weaker gravitational pull. ### **Summary:** - **On Earth:** In a frictionless environment, the 5 kg hammer and the 0.001 kg feather will **reach the ground at the same time** when dropped from 2 meters. - **On the Moon:** They will **still land simultaneously**, but the **fall will take longer** due to the Moon's weaker gravity. This outcome highlights the fundamental principle that in the absence of air resistance, **all objects accelerate at the same rate regardless of their mass**.

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Both the 5 kg hammer and the 0.001 kg feather will reach the ground at the same time when dropped in a frictionless environment because they both experience the same acceleration due to gravity, regardless of their mass. This principle is a fundamental aspect of Galileo's experiments, illustrating that in the absence of air resistance, all objects fall at the same rate. On the Moon, the scenario changes a bit because the gravitational acceleration is weaker (about 1/6th of Earth's). However, since there's still no air resistance, both the hammer and the feather would fall at a slower rate compared to Earth, but still hit the ground simultaneously. So, the time it takes for them to fall on the Moon would be greater than on Earth, but they'd both still land together!

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