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Daar is \( 1+2+3=6 \) dele. Ben kry: \( \frac{1}{6} \times 24=4 \) Mondlo kry: \( \frac{2}{6} \times 24-8 \quad \) Jabulani kry: \( \frac{3}{6} \times 24=12 \) Oefening 1.12 1. Verdeel 220 in die verhouding \( 3: 8 \). 2. Verdeel R3 520 in die verhouding \( 11: 12: 17 \). 3. Hanna. Sarah en Mthunzi koop 'n kompetisiekaartje vir R60. Hanna dra R15 by, Sarah R21 en Mthunzi R24. Hulle wen R4 000. Bereken die bedrag wat elkeen behoort te kry.

Ask by Fernandez Bush. in South Africa
Feb 03,2025

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1. **Verdeling van R220 in 3:8 verhouding:** - **R60** en **R160** 2. **Verdeling van R3 520 in 11:12:17 verhouding:** - **R968**, **R1 056**, en **R1 496** 3. **Verdeling van R4 000 wedervan Hanna, Sarah en Mthunzi se inleg van R15, R21, en R24:** - **Hanna**: R1 000 - **Sarah**: R1 400 - **Mthunzi**: R1 600

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Om 220 in die verhouding \(3:8\) te verdeel, moet ons die totale eenhede tel: \(3 + 8 = 11\). Dan kan ons die oorblywende bedrag vir elkeen bereken. Hanna kry \( \frac{3}{11} \times 220 = 60\) en Mthunzi kry \( \frac{8}{11} \times 220 = 160\). Vir die tweede vraag, om R3,520 in die verhouding \(11:12:17\) te verdeel, tel ons die totale eenhede: \(11 + 12 + 17 = 40\). So, Hanna kry \( \frac{11}{40} \times 3520 = 968\), Sarah kry \( \frac{12}{40} \times 3520 = 1056\) en Mthunzi kry \( \frac{17}{40} \times 3520 = 1488\). Vir die kompetisiekaartje, tel ons eerste al die bydraes op: \(15 + 21 + 24 = 60\). Die totale bedrag is dus R4000. Elke persoon se aandeel is gebaseer op hul bydraes: Hanna se aandeel is \( \frac{15}{60} \times 4000 = 1000\), en so aan vir Sarah en Mthunzi, wat R1400 en R1600 sal ontvang.

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