(d) The graph of $$ y=1-\frac{2}{x^{2}} $$ cuts the positive $$ x $$-axis at $$ A $$. $$ B $$ is the point $$ (0,-2) $$ (i) Write down the co-ordinates of $$ A $$.

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To find the coordinates of point $$ A $$ where the graph of $$ y = 1 - \frac{2}{x^2} $$ intersects the positive $$ x $$-axis, follow these steps:

1. **Intersection with the $$ x $$-axis:**
   
   At the $$ x $$-axis, the $$ y $$-coordinate is 0. So, set $$ y = 0 $$:

$$
   0 = 1 - \frac{2}{x^2}
   $$

2. **Solve for $$ x $$:**

$$
   \frac{2}{x^2} = 1 \implies x^2 = 2 \implies x = \sqrt{2} \quad (\text{since } x > 0)
   $$

3. **Coordinates of $$ A $$:**

$$
   A = \left( \sqrt{2}, \, 0 \right)
   $$

**Answer:**  
(i) The coordinates of $$ A $$ are $$ \left( \sqrt{2},\; 0 \right) $$.
The coordinates of point $$ A $$ are $$ \left( \sqrt{2},\; 0 \right) $$.

(d) The graph of cuts the positive -axis at .
is the point
(i) Write down the co-ordinates of .

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(d) The graph of cuts the positive -axis at . is the point (i) Write down the co-ordinates of .