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Chepter 1 H orcwenk Question 27 of 30 (1 poinil) | Qucstion Attempt 1 of 3 The natural abundances of elements in the human body, expressed as percent by mass, are oxygen (O), 65 percent; carbon (C), 18 percent; hydrogen (H). 10. percent; nitrogen ( N ), 3.0 percent; calcium (Ca), 1.6 percent; phosphorus ( P ), 1.2 percent; all other elements, 1.2 percent. Catculate the mass in grams of each element in the body of a 77 kg person. Round each of your answers to 2 significant digits. \( \square \) g 0 \( \square \) If gH \( \square \) 8 N \( \square \) ECa \( \square \) \( g \mathrm{P} \) \( \square \) g all other elements

Ask by Griffiths Gonzalez. in the United States
Feb 03,2025

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Tutor-Verified Answer

Answer

- **Oxygen (O):** 50,000 g - **Carbon (C):** 13,860 g - **Hydrogen (H):** 7,700 g - **Nitrogen (N):** 2,310 g - **Calcium (Ca):** 1,232 g - **Phosphorus (P):** 924 g - **All Other Elements:** 924 g

Solution

To calculate the mass of each element in the body of a 77 kg (77,000 g) person based on their natural abundances, follow these steps: 1. **Convert Body Weight to Grams:** \[ 77 \, \text{kg} = 77,000 \, \text{g} \] 2. **Calculate Mass of Each Element:** - **Oxygen (O) - 65%:** \[ \text{Mass of O} = 0.65 \times 77,000 \, \text{g} = 50,050 \, \text{g} \approx 5.0 \times 10^4 \, \text{g} \] - **Carbon (C) - 18%:** \[ \text{Mass of C} = 0.18 \times 77,000 \, \text{g} = 13,860 \, \text{g} \approx 1.4 \times 10^4 \, \text{g} \] - **Hydrogen (H) - 10%:** \[ \text{Mass of H} = 0.10 \times 77,000 \, \text{g} = 7,700 \, \text{g} \approx 7.7 \times 10^3 \, \text{g} \] - **Nitrogen (N) - 3.0%:** \[ \text{Mass of N} = 0.03 \times 77,000 \, \text{g} = 2,310 \, \text{g} \approx 2.3 \times 10^3 \, \text{g} \] - **Calcium (Ca) - 1.6%:** \[ \text{Mass of Ca} = 0.016 \times 77,000 \, \text{g} = 1,232 \, \text{g} \approx 1.2 \times 10^3 \, \text{g} \] - **Phosphorus (P) - 1.2%:** \[ \text{Mass of P} = 0.012 \times 77,000 \, \text{g} = 924 \, \text{g} \approx 9.2 \times 10^2 \, \text{g} \] - **All Other Elements - 1.2%:** \[ \text{Mass of Other Elements} = 0.012 \times 77,000 \, \text{g} = 924 \, \text{g} \approx 9.2 \times 10^2 \, \text{g} \] 3. **Summary of Masses (Rounded to Two Significant Digits):** | Element | Mass (g) | |-----------------------|-----------------| | **Oxygen (O)** | \(5.0 \times 10^4\) g | | **Carbon (C)** | \(1.4 \times 10^4\) g | | **Hydrogen (H)** | \(7.7 \times 10^3\) g | | **Nitrogen (N)** | \(2.3 \times 10^3\) g | | **Calcium (Ca)** | \(1.2 \times 10^3\) g | | **Phosphorus (P)** | \(9.2 \times 10^2\) g | | **All Other Elements**| \(9.2 \times 10^2\) g |

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To find the mass of each element in a 77 kg person, you start by converting the weight to grams (1 kg = 1000 g), which gives you 77,000 g. You can then calculate the mass of each element using their percent composition. For example, for oxygen, you would multiply 77,000 g by 0.65 (or 65%). Doing this for all elements will help you arrive at the mass of each one, allowing you to appreciate the intricacies of the human body! Now, after calculating, you'll find: Oxygen = 50,000 g, Carbon = 14,000 g, Hydrogen = 7,700 g, Nitrogen = 2,310 g, Calcium = 1,232 g, Phosphorus = 924 g, and all other elements combined = approximately 924 g. These calculations illustrate just how vital each element is for our existence!

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