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Make \( g \) the subject of \( e=\sqrt{\frac{7 g+5}{11+2 g}} \)

Ask by Carroll Ellis. in Qatar
Jan 18,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\( g = \frac{11e^{2} - 5}{7 - 2e^{2}} \)

Solution

To make \( g \) the subject of the equation \( e = \sqrt{\frac{7g + 5}{11 + 2g}} \), follow these steps: 1. **Square Both Sides** Start by eliminating the square root by squaring both sides of the equation: \[ e^2 = \frac{7g + 5}{11 + 2g} \] 2. **Multiply Both Sides by the Denominator** This removes the fraction: \[ e^2 (11 + 2g) = 7g + 5 \] \[ 11e^2 + 2e^2g = 7g + 5 \] 3. **Gather Like Terms** Bring all terms containing \( g \) to one side and the constant terms to the other: \[ 2e^2g - 7g = 5 - 11e^2 \] 4. **Factor Out \( g \)** Factor \( g \) from the left side: \[ g(2e^2 - 7) = 5 - 11e^2 \] 5. **Solve for \( g \)** Finally, isolate \( g \) by dividing both sides by \( (2e^2 - 7) \): \[ g = \frac{5 - 11e^2}{2e^2 - 7} \] To present the equation with a positive denominator, you can multiply both the numerator and the denominator by \(-1\): \[ g = \frac{11e^2 - 5}{7 - 2e^2} \] **Final Answer:** \[ g = \frac{11\,e^{2} - 5}{\,7\; -\; 2\,e^{2}\,} \]

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The Deep Dive

To make \( g \) the subject of the equation \( e=\sqrt{\frac{7 g+5}{11+2 g}} \), we start by squaring both sides to eliminate the square root: \[ e^2 = \frac{7g + 5}{11 + 2g} \] Next, we can cross-multiply to eliminate the fraction: \[ e^2(11 + 2g) = 7g + 5 \] Expanding the left side gives: \[ 11e^2 + 2ge^2 = 7g + 5 \] Now, we need to rearrange the equation to isolate \( g \). Let's move all terms involving \( g \) to one side and constant terms to the other: \[ 2ge^2 - 7g = 5 - 11e^2 \] Factoring \( g \) out from the left side gives: \[ g(2e^2 - 7) = 5 - 11e^2 \] Now, we can solve for \( g \) by dividing both sides by \( 2e^2 - 7 \): \[ g = \frac{5 - 11e^2}{2e^2 - 7} \] And that's our final expression with \( g \) as the subject!

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