Apply 7. Akira and Jen are competing to see who can sell the most tickets for the Winter Dance On Monday, Akira sold 20 and then sold 30 per day after that, Jen sold 50 on Monday and the sold 20 per day after that. This situation can be represented with the system \( y=30 x+20 \) a \( y=20 x+50 \), where \( x \) is the number of days after the first day, and \( y \) is the total tickets sol After how many days did they sell the same number of tickets?

To find out how many days it takes for Akira and Jen to sell the same number of tickets, we set their equations equal to each other: \[ 30x + 20 = 20x + 50 \] Next, we solve for \(x\): 1. Subtract \(20x\) from both sides: \[ 10x + 20 = 50 \] 2. Subtract 20 from both sides: \[ 10x = 30 \] 3. Divide by 10: \[ x = 3 \] So, Akira and Jen will sell the same number of tickets after 3 days. Now, let's check their ticket sales after 3 days: - Akira: \(20 + 3 \times 30 = 20 + 90 = 110\) - Jen: \(50 + 3 \times 20 = 50 + 60 = 110\) Both sold 110 tickets after 3 days! In conclusion, it takes 3 days for Akira and Jen to have the same total ticket sales, both reaching 110 tickets!