Question
Real Tutor Solution
Tutor-Verified Answer
Answer
\( c = 5 \)
Solution
To solve the equation \( 4(c + 2) = 28 \) for \( c \), follow these steps:
1. **Divide both sides by 4** to eliminate the coefficient of the parentheses:
\[
\frac{4(c + 2)}{4} = \frac{28}{4}
\]
Simplifying both sides:
\[
c + 2 = 7
\]
2. **Subtract 2 from both sides** to isolate \( c \):
\[
c + 2 - 2 = 7 - 2
\]
Simplifying both sides:
\[
c = 5
\]
3. **Solution:** \( c = 5 \)
4. **Verification:**
Substitute \( c = 5 \) back into the original equation to ensure it's correct:
\[
4(5 + 2) = 4 \times 7 = 28
\]
Since both sides equal 28, the solution \( c = 5 \) is correct.
**Final Answer:** \( c = 5 \)
Reviewed and approved by the UpStudy tutoring team
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Simplify this solution Bonus Knowledge
To solve the equation \( 4(c+2)=28 \), start by dividing both sides by 4 to simplify it. This gives you \( c+2=7 \). Next, subtract 2 from both sides to isolate \( c \). Thus, \( c=7-2 \), resulting in \( c=5 \). So, the solution to the equation is \( c=5 \).
