Question
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Multiply or divide, as indicated. Simplify the answer. 2) \( \frac{\sqrt{-112}}{\sqrt{-7}} \)

Ask by Alexander Weston. in Qatar
Jan 22,2025

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Tutor-Verified Answer

Answer

The simplified answer is 4.

Solution

To simplify the expression \( \frac{\sqrt{-112}}{\sqrt{-7}} \), follow these steps: 1. **Express Square Roots of Negative Numbers:** Recall that \( \sqrt{-a} = i\sqrt{a} \), where \( i \) is the imaginary unit (\( i = \sqrt{-1} \)). \[ \frac{\sqrt{-112}}{\sqrt{-7}} = \frac{i\sqrt{112}}{i\sqrt{7}} \] 2. **Simplify the Imaginary Units:** The \( i \) terms cancel out: \[ \frac{i\sqrt{112}}{i\sqrt{7}} = \frac{\sqrt{112}}{\sqrt{7}} \] 3. **Divide the Radicands:** \[ \frac{\sqrt{112}}{\sqrt{7}} = \sqrt{\frac{112}{7}} = \sqrt{16} \] 4. **Simplify the Square Root:** \[ \sqrt{16} = 4 \] **Final Answer:** \[ 4 \]

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Bonus Knowledge

To simplify \( \frac{\sqrt{-112}}{\sqrt{-7}} \), we can first rewrite the square roots using imaginary numbers. 1. \(\sqrt{-112} = \sqrt{112}i = \sqrt{16 \times 7}i = 4\sqrt{7}i\). 2. \(\sqrt{-7} = \sqrt{7}i\). Now, substituting these into the expression gives us: \[ \frac{\sqrt{-112}}{\sqrt{-7}} = \frac{4\sqrt{7}i}{\sqrt{7}i} \] The \(i\) terms cancel out, and we can also cancel \(\sqrt{7}\): \[ \frac{4\sqrt{7}}{\sqrt{7}} = 4 \] Thus, the simplified answer is \(4\).

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