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Rewrite in slope-intercept form: \[ -2 x+2 y=16 \]

Ask by Wood Norris. in the United States
Jan 24,2025

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Answer

The slope-intercept form of the equation is \( y = x + 8 \).

Solution

To rewrite the equation \(-2x + 2y = 16\) in slope-intercept form \((y = mx + b)\), follow these steps: 1. **Isolate the \(y\)-term:** \[ -2x + 2y = 16 \quad \Rightarrow \quad 2y = 2x + 16 \] 2. **Solve for \(y\):** \[ y = \frac{2x + 16}{2} \quad \Rightarrow \quad y = x + 8 \] So, the slope-intercept form of the equation is: \[ \boxed{y = x + 8} \]

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To rewrite the equation \(-2x + 2y = 16\) in slope-intercept form (which is \(y = mx + b\)), we need to solve for \(y\). First, add \(2x\) to both sides: \[ 2y = 2x + 16 \] Now, divide every term by \(2\): \[ y = x + 8 \] So, the slope-intercept form of the equation is \(y = x + 8\).

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