Question
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Consider the function \( f(x)=\sqrt{4-x} \). Find the formula for the inverse function.

Ask by Montgomery Santiago. in the United States
Jan 26,2025

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Tutor-Verified Answer

Answer

The inverse function is \( f^{-1}(x) = 4 - x^2 \).

Solution

To find the inverse of the function \( f(x) = \sqrt{4 - x} \), follow these steps: 1. **Start with the original equation:** \[ y = \sqrt{4 - x} \] 2. **Solve for \( x \) in terms of \( y \):** \[ y^2 = 4 - x \] \[ x = 4 - y^2 \] 3. **Express the inverse function:** \[ f^{-1}(y) = 4 - y^2 \] Typically, we replace \( y \) with \( x \) to express the inverse function in standard form: \[ f^{-1}(x) = 4 - x^2 \] **Domain and Range Considerations:** - **Original Function \( f(x) = \sqrt{4 - x} \):** - **Domain:** \( x \leq 4 \) (since the expression inside the square root must be non-negative) - **Range:** \( y \geq 0 \) (since square roots are non-negative) - **Inverse Function \( f^{-1}(x) = 4 - x^2 \):** - **Domain:** \( x \geq 0 \) (based on the range of the original function) - **Range:** \( y \leq 4 \) **Final Answer:** \[ f^{-1}(x) = 4 - x^2 \]

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To find the inverse function of \( f(x) = \sqrt{4 - x} \), we start by setting \( y = f(x) \). Therefore, we have: \[ y = \sqrt{4 - x} \] Next, we swap \( x \) and \( y \): \[ x = \sqrt{4 - y} \] Now, we solve for \( y \). First, we square both sides: \[ x^2 = 4 - y \] Rearranging gives us: \[ y = 4 - x^2 \] Thus, the inverse function is: \[ f^{-1}(x) = 4 - x^2 \] And remember, this inverse is only valid for \( x \) in the range that corresponds to the domain of the original function \( f \). So, the formula for the inverse function is: \[ f^{-1}(x) = 4 - x^2 \]

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