Solve by the substitution method. (If there is no solution, enter NO SOLUTION. Use the parameters \( x \) and \( y \) as necessary.) \[ \begin{aligned} 2 x-3 y=4 \\ x=5 y+2\end{aligned} \] \( (x, y)=( \)
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To solve the system of equations using the substitution method, we start with the second equation: 1. From the equation \( x = 5y + 2 \), we can substitute \( x \) into the first equation \( 2x - 3y = 4 \): \[ 2(5y + 2) - 3y = 4 \] 2. Now expand and simplify: \[ 10y + 4 - 3y = 4 \] \[ 10y - 3y + 4 = 4 \] \[ 7y + 4 = 4 \] 3. Next, isolate \( y \): \[ 7y = 4 - 4 \] \[ 7y = 0 \] \[ y = 0 \] 4. Now substitute \( y = 0 \) back into the expression for \( x \): \[ x = 5(0) + 2 = 2 \] Thus, the solution to the system is: \( (x, y) = (2, 0) \)