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11. Find the distance between \( (-2,5) \) and \( (4,3) \). Keep your answer in \( \quad * \ldots / 1 \) radical form. \( \quad \vee \) (copy and paste this symbol)

Ask by Cummings Barrett. in the United States
Jan 30,2025

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Answer

The distance between the points \((-2, 5)\) and \((4, 3)\) is \(2\sqrt{10} \quad \vee\).

Solution

To find the distance between the points \((-2, 5)\) and \((4, 3)\), you can use the distance formula: \[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Plugging in the given points: \[ \begin{align*} x_1 &= -2, \quad y_1 = 5 \\ x_2 &= 4, \quad y_2 = 3 \\ \end{align*} \] Calculate the differences: \[ \begin{align*} x_2 - x_1 &= 4 - (-2) = 6 \\ y_2 - y_1 &= 3 - 5 = -2 \\ \end{align*} \] Square the differences and add them: \[ 6^2 + (-2)^2 = 36 + 4 = 40 \] Take the square root to find the distance: \[ \text{Distance} = \sqrt{40} = \sqrt{4 \times 10} = 2\sqrt{10} \] So, the distance between the points is: \[ 2\sqrt{10} \quad \vee \]

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To find the distance between the points \( (-2,5) \) and \( (4,3) \), you can use the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Plugging in the values: \[ d = \sqrt{(4 - (-2))^2 + (3 - 5)^2} = \sqrt{(4 + 2)^2 + (-2)^2} = \sqrt{6^2 + (-2)^2} = \sqrt{36 + 4} = \sqrt{40} \] Thus, the distance is \( \sqrt{40} = \sqrt{4 \cdot 10} = 2\sqrt{10} \). Now, isn't it fascinating how this formula not only helps calculate distances in geometry but is also deeply rooted in the Pythagorean theorem? That clever connection shows us that distances in a flat plane can be visualized as the hypotenuse of a right triangle! In real life, you can apply the concepts of distance calculations in various scenarios, such as planning travel routes, determining the closest locations (like finding a café near you), or even in fields like robotics where understanding the distance between two points is crucial for navigation and movement. It’s all about measuring that perfect path!

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