Question
For the function, evaluate the following. \[ f(x, y)=x^{2}-y-x y+1 \] (o) \( f(0,0) \) 1 (b) \( f(1,0) \) 2
Ask by Curry Little. in the United States
Jan 20,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\( f(0, 0) = 1 \) and \( f(1, 0) = 2 \).
Solution
Certainly! Let's evaluate the function \( f(x, y) = x^{2} - y - x y + 1 \) at the specified points.
### (a) \( f(0, 0) \)
Plug in \( x = 0 \) and \( y = 0 \) into the function:
\[
f(0, 0) = (0)^2 - 0 - (0)(0) + 1 = 0 - 0 - 0 + 1 = 1
\]
**Result:** \( f(0, 0) = 1 \)
---
### (b) \( f(1, 0) \)
Plug in \( x = 1 \) and \( y = 0 \) into the function:
\[
f(1, 0) = (1)^2 - 0 - (1)(0) + 1 = 1 - 0 - 0 + 1 = 2
\]
**Result:** \( f(1, 0) = 2 \)
---
Your evaluations are correct:
- \( f(0, 0) = 1 \)
- \( f(1, 0) = 2 \)
If you have any further questions or need additional evaluations, feel free to ask!
Reviewed and approved by the UpStudy tutoring team
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Extra Insights
To evaluate the function \( f(x, y)=x^{2}-y-x y+1 \) at the given points: For \( f(0,0) \): \[ f(0,0) = 0^{2} - 0 - 0 \cdot 0 + 1 = 0 - 0 - 0 + 1 = 1 \] For \( f(1,0) \): \[ f(1,0) = 1^{2} - 0 - 1 \cdot 0 + 1 = 1 - 0 - 0 + 1 = 2 \] So, \( f(0,0) = 1 \) and \( f(1,0) = 2 \).